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8 x + 6 y + 3 = 03 \pi / ( \text { and } ) 4 x + 3 y + 1 = 0 |
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Answer» ii) 8x+6y= -3 .....(1 4x+3y = -1.......(2so multiply second eq by 2 and subtract it from eq 1we get 0= 1 which is absurd so there is no solution for this pair of equation. tell me what I solve in this question |
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