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8. whose fifth term is 14 and 12th term is 0. |
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Answer» ong>Step-by-step explanation: 5th term=14 => a+4d=14 --------(1) 12TH term=0 =>a+11d=0 --------(2) subtracting (1) and (2) a+11d=0 a+4d=14 7d= -14 d= -7 substituting value of d in (1) a+4(-7)=14 a=14+28 =>a=42 therefore the AP is 42, 42+(-7), 42+2(-7)... => AP= 42, 35, 28... |
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