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8. The value of a machine worth? 500000 is depreciating at the rate of 10% every year.how many years will its value be reduced to364500?

Answer»

Original value P= 500000Depreciated value A= 364500R = 10%No. Of years = n

A = P(1 - R/100)^n364500 = 500000(1-10/100)^n3645/5000 = (9/10)^n(9/10)^3 = (9/10)^nn = 3

No. Of years = 3 yrs



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