8. The molarity of a 0.2 N Na 2 C03 solution will be: (a) 0.05 M(b) 0.2 M(c) 0.1 M(d) 0.4M

8. The molarity of a 0.2 N Na 2 C03 solution will be: (a) 0.05 M(b)

1.	8. The molarity of a 0.2 N Na 2 C03 solution will be: (a) 0.05 M(b) 0.2 M(c) 0.1 M(d) 0.4M
Answer» c) 0.1MExplanation:N-FACTOR far Na2co3 = 2∵ The n-factor of such SALTS is defined as the number of moles of electrons EXCHANGED (lost or gained) by ONE mole of the salt. And there is the exchange of 2 electrons so its n factor is 2Therefore, Normality = n-fator × molarityMolarity = 0.2/2 =0.1 MThanks! Hope it will help you.Good LucK!