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Answer» Correct Statement is The equation of a straight line passing through the POINT (2,-7) and parallel to x-axis is (a) x = 2 (c) y = - 7 (b) x = 7 (d) y = 2 
A line - passes through the point (2, - 7)
and 
Concept USED :- Slope - point form of a line Let us assume a line which passes through the point (a, b) and having slope 'm', then equation of line is 

Given that - A line passes through the point (2, - 7) and parallel to x - axis.
Since, - Line is parallel to x- axis.

Now, We know that - Equation of line is given by

where, 


On substituting all these values in above equation, we get 



─━─━─━─━─━─━─━─━─━─━─━─━─ Additional InformationDifferent forms of equations of a straight line 1. Equations of horizontal and vertical lines - Equation of the lines which are horizontal or parallel to the X-axis is y = a, where a is the y – coordinate of the POINTS on the line.
- Similarly, equation of a straight line which is vertical or parallel to Y-axis is x = a, where a is the x-coordinate of the points on the line.
2. Point-slope form equation of line - Consider a non-vertical line L whose slope is m, A(x,y) be an arbitrary point on the line and P(a, b) be the fixed point on the same line. Equation of line is given by y - b = m(x - a)
3. Slope-intercept form equation of line - Consider a line whose slope is m which cuts the Y-axis at a distance ‘a’ from the origin. Then the distance a is called the y– intercept of the line. The point at which the line cuts y-axis will be (0,a). Then equation of line is given by y = mx + a.
4. Intercept Form of Line - Consider a line L having x– intercept a and y– intercept b, then the line passes through X– axis at (a,0) and Y– axis at (0,b). Equation of line is given by x/a + y/b = 1.
5. Normal form of Line - Consider a perpendicular from the origin having length p to line L and it makes an angle β with the positive X-axis. Then, equation of line is given by x cosβ + y sinβ = p.
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