Saved Bookmarks
| 1. |
8. Saurabh invests 48,000 for 7 years at 10%per annum compound interest. Calculate :(i) the interest for the first year.(ii) the amount at the end of the second year.(iii) the interest for the third year. |
|
Answer» Compounding is once at the end of the year.So the interest for n year is P (1+r/100)^n - P, where P = principle, r = rate of interest and n = number of years..Given P= 48000. r = 7 and n = 1. Substituting these values in the formula, we get:Interest for the first year = 48000(1+7/100)^1 - 48000 = 480*7 = 3360 rupees. |
|