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8. Particle A is at top of a tower of height 100 m. Particle B is at the bottom of the same tower. Inthe time taken by the particles to meet if they are thrown as given below for three separate cases.(a) A is dropped & Bis projected vertically upwards with a speed of 50 m/s.(b) A is projected downwards with a speed of 25 m/s & Bis projected upwards with a speed t50 m/s |
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Answer» 2 sec 4/3 secExplanation:Case 1 :A is Dropped B is VERTICALLY upward thrown with velocity of 50 m/sDistance to be covered by both = 100 mLet say After Time T they MeetUsing S = Ut + (1/2)at²Distance Covered by A = 0*t + (1/2)gt²Distance covered by B = 50T - (1/2)gt²(1/2)gt² + 50t - (1/2)gt² = 50t50t = 100=> t = 2 secCase 2 :A is Vertically DOWNWARD thrown with velocity of 25 m/sB is Vertically upward thrown with velocity of 50 m/sDistance to be covered by both = 100 mLet say After Time T they MeetUsing S = Ut + (1/2)at²Distance Covered by A = 25*t + (1/2)gt²Distance covered by B = 50t - (1/2)gt²25t + (1/2)gt² + 50t - (1/2)gt² = 75t75t = 100=> t = 4/3 sec |
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