8% of the voters in an election did not cast their votes. In this election, there were only two candidates. The winner by obtaining 48% of total votes, defeated his rival by 1100 votes. The total number of voters in the election was :(a) 21000 (b) 23500 (c) 22000 (d) 27500Aligarh Muslim University +2 Science/Diploma Entrance Test - 2018-19

8% of the voters in an election did not cast their votes. In this elec

1.	8% of the voters in an election did not cast their votes. In this election, there were only two candidates. The winner by obtaining 48% of total votes, defeated his rival by 1100 votes. The total number of voters in the election was :(a) 21000 (b) 23500 (c) 22000 (d) 27500Aligarh Muslim University +2 Science/Diploma Entrance Test - 2018-19
Answer» Hello MATE! Let total number of votes be x Now, 1st CANDIDATE won 48% of total votes = 48x/100 But, 8% from total voters don't give VOTE ; so votes gives actually = x - 8x/100 = 92x/100 Hmn, now 2nd candidate must have got 92x/100 - 48x/100 = 44x/100, then Now, 2nd candidate lost by 1st candidate by 1100 votes :- 48x/100 = 44x/100 + 1100 48x/100 - 44x/100 = 1100 4x/100 = 1100 x= 100/4 × 1100 x = 27,500 votes are polled Hope it helps☺!

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