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Answer» Consider 252 and 324. here, a=324 and b=252 by euclid's division lemma- a=bq+r, 0< or= r<b 324=2521+72 252=723+36 72=362+0 therefore, HCF(252, 324)=36 Now consider 36 and 180. here a=180 and b=36. by euclid's division lemma- a=bq+r, 0< or = r < b 180=365+0 therefore, HCF(180, 36)=36 Hence, HCF(180, 252, 324)=36 please like the solution 👍 ✔️

Answer»

Consider 252 and 324. here, a=324 and b=252

by euclid's division lemma-

a=bq+r, 0< or= r<b

324=252*1+72

252=72*3+36

72=36*2+0

therefore, HCF(252, 324)=36

Now consider 36 and 180. here a=180 and b=36.

by euclid's division lemma- a=bq+r, 0< or = r < b

180=36*5+0

therefore, HCF(180, 36)=36

Hence, HCF(180, 252, 324)=36

please like the solution 👍 ✔️

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