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8. In Figure 8a and 8b, AB CD. Find the value of x.At C3rB 0 Fig. 8a |
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Answer» 2. 3x+2x=180 5x=180 x=180/5=36 i) ang(ABD)+ang(CDB)=180°....... (Because AB and CD are parallel lines) ang(CDB)=180°-65°=115° ang(ODE)=ang(BDC)........ (Opposite angles) ang (ODE)=115° in triangle ODE x+30°+115°=180°x+145°=180°x=180°-145°x=35° ii) 2x+3x=180°........ (interior angles)5x=180°x=36° |
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