1.

8. If tan(01 - 02) = 73 and sec(01 + 02) = 7a then sin20s+ tan382 is equal to(a) 73 (b) 2 (c) 3 (d) 1​

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Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual TWO DISTINCT solutions, then the two solutions must be same i.e. DISCRIMINANT = 0.

Hence we GET that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.


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