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8 Find the points on the X-axis which are at a distanceof 215 from the point (7-4). How many such pointsare there?CBSE 2011

Answer»

Co-ordinates of point onx-axis be (x, 0) which is at a distance of 2√5 from point (7, –4).

Distance between two points A(x1, y1) and B(x2, y2) is AB =(x2-x1)2+(y2-y1)2

It is given that the distance between points (x, 0) and (7, –4) is 2√5.

⇒ [ ( 7 -x )2+ ( -4 – 0)2] = 2√5 .

Squaring both the sides, we obtain

⇒ ( 7 – x)2+ 16 = 20

⇒ 49 + x2– 14x + 16 = 20

⇒ x2– 14x + 45 = 0

⇒ x2– 5x – 9x + 45 = 0

⇒ x( x – 5) – 9( x – 5) = 0

⇒ ( x – 9) ( x – 5) = 0

∴x= 5 and 9.

Hence, there are two points i.e., (5, 0) and (9, 0).



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