1.

8. Find the equation of the straight line which passes through the point (3,-2) and cuts off osiheintercepts on the x and y-axes which are in the ratio 4:3.a line W

Answer»

The equation of the line cutting off positive intercepts in the ratio 4:3

x/4a+y/3b=1................(1)

thus passes through (3,-2)

⇒3/4a+ -2/3a=1multiply both sides by 12a⇒9-8=4a=>a=1/12

4a=4/12=1/33a=3/12=1/4

substituting in eq(1)x/1/3+y/1/4=13x+4y=1or 3x+4y-1=0This is the required equation

The line x + y = a passes through (1, −2)

∴ 1-2=a⇒a=-1

Hence, the equation of the line is x+y=-1



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