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8.A vessel of irregular shape has a volume 'V'.It is first evacuated amd coupled with a vesselof 4L capacity at 35°C and 10 atm pressure.If the final pressure in both the vessels is 3atm,calculate the volume V.1) 9.3 L 2) 8 L 3) 6L 4) 8.3 L​

Answer»

Hi,

Answer:

The volume “V” of the irregular shape vessel is 9.8 L.

Explanation:

Given data:

The volume of the irregular shape vessel is “V”

The other vessel has a volume Vo = 4 L at pressure, Po =10 atm and temperature, T = 35°C

The final pressure of the vessels after coupling them = 3 atm

To find: Volume “V”

SINCE pressure in the other vessel is reduced from 10 atm to 3 atm after being coupled with the irregular vessel. Therefore, change in the pressure in the other vessel = 10 – 3 = 7 atm

Using the Ideal Gas Law,

PV = nRT

Moles of substance in the irregular vessel after coupling = PV / RT = 3 * V / RT ….(i)

Moles of substance in the other vessel after coupling = (change in pressure) * Vo / RT = 7 * 4 / RT ….(ii)

Equating (i) & (ii), we get

3 * V / RT = 7 * 4 / RT

Or, 3 * V = 7 * 4

Or, V = 9.8 L

Hope this helps!!!!


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