1.

( 8 a ^ { 3 } \div 27 x ^ { - 3 } ) ^ { \frac { 2 } { 3 } } \times ( 64 a ^ { 3 } \div 27 x ^ { - 3 } ) ^ { \frac { - 2 } { 3 } }

Answer»

(8a^3 ÷ 27x^-3)^2/3 * (64a^3 ÷ 27x^-3)^-2/3

=[(2a)^3*2/3 ÷ (3x)^-3*2/3)]* [(4a)^3*-2/3 ÷ (3x)^-3*-2/3]

= (4a^2 * 9x^2) *[(1/16a^2)÷9x^2]

= (4a^2*9x^2) / (16a^2*9x^2)

= 1/4



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