$ (8) 3(y+8)=10(y-4)+8 $$ (11) \frac{b+(b+1)+(b+2)}{4}=21 $ – InterviewSolution

1.	$ (8) 3(y+8)=10(y-4)+8 $$ (11) \frac{b+(b+1)+(b+2)}{4}=21 $
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