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8.1 If α, β are zeroes of r2-6x + k. what is the value of k if 3a + 2β-207(b) S(d) -8 |
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Answer» We know that α and β are zeroes of the polynomial f(x) = ax^2+ bx + cα+ β = -b / a αβ = c / a.Given thatα and β are zeroes of x2- 6x + k = 0.α+ β = 6 -----------------(1) ,αβ = kgiven that 3 α + 2 β = 20 -------------------(2)Solving (1) and (2) we getα = 14 ,β = - 8But αβ = k ⇒ k = -112 . |
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