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73g of conc.HCL was diluted by adding 144g of water.How many gram atom of hydrogen are present in the dilute acid?Please solve it fast |
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Answer» udent,◆ Answer -Moles of hydrogen = 18 gram-atoms● Explaination -Moles of HCl are -n(HCl) = W(HCl) / M(HCl)n(HCl) = 73/36.5n(HCl) = 2 molMoles of H-atoms in HCl is -n1 = 1 × 2n1 = 2 molMoles of H2O are -n(H2O) = W(H2O) / M(H2O)n(H2O) = 144/18n(H2O) = 8 molMoles of H-atoms in H2O is -n1 = 2 × 8n1 = 16 molTotal moles of H-atoms is -n = n1 + n2n = 2 + 16n = 18 molTherefore, 18 gram atoms hydrogen are PRESENT in dilute acid.Thanks dear. Hope this helps you... |
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