735 L of a solution containing 0.34 moles of calcium hydroxide

1.	735 L of a solution containing 0.34 moles of calcium hydroxide
Answer» First we have to CALCULATE the concentration of the strong ACID HNO3: 0.34molHNO3735L=4.626×10−4M Now HNO3 is a strong acid, and DISSOCIATES completely in WATER: HNO3 → H+ + NO3-. [H+]pH=4.626×10−4M=−log[H+]=−log[4.626×10−4]=3.33 Despite the large dilution FACTOR (a small number of moles into 735 Liters), this is still quite an acidic solution, pH < 7.

Answer»

First we have to CALCULATE the concentration of the strong ACID HNO3:

0.34molHNO3735L=4.626×10−4M

Now HNO3 is a strong acid, and DISSOCIATES completely in WATER: HNO3 → H+ + NO3-.

[H+]pH=4.626×10−4M=−log[H+]=−log[4.626×10−4]=3.33

Despite the large dilution FACTOR (a small number of moles into 735 Liters), this is still quite an acidic solution, pH < 7.

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