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7. What mass of steam initially at 130°C is needed to warm 200 g of water in a 100-gglass container from 20.0°C to 50.0°C? Specific heat of container is 837J/K9°CSpecific heat of steam is 2110J/Kg CSpecific heat of water is 4186J/K9°CLatent heat of vapourisation is 2.26 10 J/Kga. 16.9 gb. 14.9 gc. 10.9 gd. 12.9 g |
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Answer» HEAT lost by steam = heat GAINED by water + heat gained by CONTAINER m(s).L +m(s).c(s).(130–100) = m(w). c(w). 30 + m(c).c(c).30 You can look up L for steam, c(s), c(w) and when you know the container material, you can look up c(c) as WELL. |
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