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7) Two bodies at rest explodes into two fragments at a height 'h' and moves horizontally opposite direction from the same height (or) a bomb at rest explodesinto two fragments at a height h and moves horizontally in opposite directionswith velocities u, and u, respectively then |
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Answer» Initial Momentum of the system is zero. So just after the BLAST momentum of the system will be zero hence particle will move in the opposite direction such that M 1 V 1 =M 2 V 2 because M 1 =M 2 hence V 1 =V 2 So when their velocity VECTORS are PERPENDICULAR to each other then dot product of their velocity will be zero hence (−10 i^ −gt J^ ).(10 i^ −gt j^ )=0hence t= g10×10 =1secExplanation:Initial Momentum of the system is zero. So just after the blast momentum of the system will be zero hence particle will move in the opposite direction such that M 1 V 1 =M 2 V 2 because M 1 =M 2 hence V 1 =V 2 So when their velocity vectors are perpendicular to each other then dot product of their velocity will be zero hence (−10 i^ −gt j^ ).(10 i^ −gt j^ )=0hence t= g10×10 =1sec |
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