7.The position x of a particle moving in a straight line,varies with t

1.	7.The position x of a particle moving in a straight line,varies with time tas x = 1/t+3. The accelerationof particle is proportional to
Answer» Explanation: x = 1/t+3 x = (t+3)^(-1) v= dx/dt = (-1)(t+3)^(-2) a = (-1)(-2)(t+3)^(-3) So, a = 2/(t+3)^3 which means that a is proportional to INVERSE of (t+3)^3 or t^3

7.The position x of a particle moving in a straight line,varies with time tas x = 1/t+3. The accelerationof particle is proportional to

Answer»

Explanation:

x = 1/t+3

x = (t+3)^(-1)

v= dx/dt = (-1)(t+3)^(-2)

a = (-1)*(-2)*(t+3)^(-3)

So, a = 2/(t+3)^3

which means that a is proportional to INVERSE of (t+3)^3 or t^3

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7.The position x of a particle moving in a straight line,varies with time tas x = 1/t+3. The accelerationof particle is proportional to​

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7.The position x of a particle moving in a straight line,varies with time tas x = 1/t+3. The accelerationof particle is proportional to