Saved Bookmarks
| 1. |
7. Prove that the area of a trapezium is halfthe sum of the parallel sides multiplied by thedistance between them. |
|
Answer» Let ABCD be a trapezium in which AB||CD.Draw CE⊥ AB and AF⊥ CD (Extended).Let AB = a, CD = b and CE = AF = h.Hencearea of trapezium ABCD = area of triangle ABC + area of triangle ADC= (1/2) ah + (1/2) bh= (1/2) h[a + b] sq units. |
|