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7. Given log 2 a, log 3-b, express in terms of a and b(0) log 6(i) log 4.8(ill) log 125yin terms of a and b |
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Answer» log6=log(2.3)=log2+log3 log(4.8)=log(48/10)=log48-log10=log(2*2*2*2*3)-14log2+log3-1 |
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