Saved Bookmarks
| 1. |
7. From a solid cylinder whose height is 2.4cm and diameter 1.4cm a conicalx cavity of the same height and same diameter is hollowed out. Find the TSA ofsolid to nearest cm? |
|
Answer» Answer: 18 sq.cm. Step-by-step explanation: Height of the cylinder, h = 2.4 m. Diameter of the cylinder, d = 1.4 m. ∴ Radius, R = 0.7 m. (i) OUTER Curved surface AREA of cylinder = 2πrh =2× 22 × (0.7) ×2.4 7 = 44. × 0.24 = 10.56 cm2 . (ii) Area of base of = πr2 (iii) Inner surface area of cylinder, = πrl =22 ×0.7×√(0.7)^2 + (2.4)^2 7 =22 × 0.7 ×2.5 7 = 5.5 cm2 ∴ Total surface area of newly formed cube = 10.56 + 1.54 + 5.5 = 17.6 cm2 . ∴ Nearest value is 18 sq.cm. |
|