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7.ABC is a triangle. A circle touches sides AB and AC produced and side BC at X, Y and Z respectively.Show that AXperimeter of AABC.

Answer»

We get thatAX=AYBX=BZCY=CZnowper of triangle ABC =ab+bc+ac=ab+(bz+zc)+ac=ab+bx+ac+cy=ax+ay=2axper of triangle ABC =2axtherefore1/2perimeter of triangle =ax



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