7.00 g of a gas occupies a volume of 4.1 L at 300 Kand 1 atm pressure.

1.	7.00 g of a gas occupies a volume of 4.1 L at 300 Kand 1 atm pressure. What is the molecular mass ofthe gas?
Answer» ANSWER: ✔✔Here is your answer ✔✔ PV= m/M RT. or. M=m×RT/PV =7.0×0.082×300/1×4.1 =42 Explanation:

7.00 g of a gas occupies a volume of 4.1 L at 300 Kand 1 atm pressure. What is the molecular mass ofthe gas?

Answer»

✔✔Here is your answer ✔✔

PV= m/M RT. or. M=m×RT/PV

=7.0×0.082×300/1×4.1

=42

Explanation: