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6sec . Its speed was its passes the second point is 45m/a. What is its acceleration and the speed at the first point |
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Answer» Answer: Answer and EXPLANATION: The DISTANCE travelled is, s = 180 m . The time TAKEN is, t = 6 s . The velocity is, v = 45 m / s . The EXPRESSION for the initial velocity is given as, u = v − a t Here, a is the ACCELERATION. Substituting the values in the above expression, u = 45 − 6 a The expression for the acceleration is given as, a = 2 ( s − u t ) t 2 Substituting the values in the above expression, a = 2 ( 180 − ( 45 − 6 a ) 6 ) 6 2 18 a = 36 a − 180 a = 10 m / s 2 Thus, the acceleration is 10 m / s 2 . |
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