Saved Bookmarks
| 1. |
6In the given figureIf 4B 40° then find) BAC(i) ZACDAACB is a right angled triangle at C and CD L AB(ii) ZBCDProof |
|
Answer» BAC = 180 - B - C = 180 - 40 - 90 = 50ACD = C - (180-B-CDB)=90-(180-40-90)=40BCD = 180-B-CDB=180-40-90=50 |
|