1.

6In the given figureIf 4B 40° then find) BAC(i) ZACDAACB is a right angled triangle at C and CD L AB(ii) ZBCDProof

Answer»

BAC = 180 - B - C = 180 - 40 - 90 = 50ACD = C - (180-B-CDB)=90-(180-40-90)=40BCD = 180-B-CDB=180-40-90=50



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