6In the fig. STOR. If PS-2.4cm, SR = 3.6cm and PQ-5 cm. Find PTPA P

1.	6In the fig. STOR. If PS-2.4cm, SR = 3.6cm and PQ-5 cm. Find PTPA P
Answer» Given: ST \|\| RQ PS= 3 cm SR = 4cm We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides. ar(∆PST) /ar(∆PRQ)= (PS)²/(PR)² ar(∆PST) /ar(∆PRQ)= 3²/(PS+SR)² ar(∆PST) /ar(∆PRQ)= 9/(3+4)²= 9/7²=9/49 Hence, the required ratio ar(∆PST) :ar(∆PRQ)= 9:49

Answer»

Given:

ST || RQ

PS= 3 cm

SR = 4cm

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of their corresponding sides.

ar(∆PST) /ar(∆PRQ)= (PS)²/(PR)²

ar(∆PST) /ar(∆PRQ)= 3²/(PS+SR)²

ar(∆PST) /ar(∆PRQ)= 9/(3+4)²= 9/7²=9/49

Hence, the required ratio ar(∆PST) :ar(∆PRQ)= 9:49

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