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6g H2 react with 8g oxygen to form water. after the completion of the reaction what is the limiting reagent |
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Answer» O2→2H2O10 G of hydrogen (molar mass 2 g/mol) = 2 g/mol 10 g = 5 mol 64 of OXYGEN (molar mass 32 g/mol) = 32 g/mol 64 g = 2 mol Explanation: As per the balanced chemical EQUATION, 1 mole of oxygen will REACT with 2 moles of hydrogen to form 2 moles of water. 2 moles of oxygen will react with 2×2=4 moles of hydrogen to form 4 moles of water. Here, oxygen is the LIMITING reagent and hydrogen is the excess reagent. |
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