1.

6er).Find the smallest number which when divided by 28 and 32leaves remainder 8 and 12 respectively.Hint: First Find LCM (smallest number). Required number =LCM - (8+12)​

Answer»

ANSWER:cvxb

Step-by-step EXPLANATION: v

gccgcmcgcb  cgfcb cbfjgnc bxxzxgcmh



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