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6cubedis expressed as the sum of consecutive odd numbers as:(A) 23+25+27+29+31 (B) 31+33+35+37+39+41(C) 13+15 +17+19+21+23 (D) 21+23+25+27+29 |
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Answer» answer is OPTION (b) there is no TRICK to solve this. first we have to TAKE out the cube of 6 which ID equal to 216 than we have to simply add values given in the option. if one of the options has its sum equal to 216 than it is correct checking option (a) 23+25+27+29+31=135 ( it is not equal to 216) checking option (b) 31+33+35+37+39+41=216 (it is equal to 216) so option(b) is the correct answer. |
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