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6a³+3a²-3afactorise it |
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Answer» ong>Answer: Write a −3a +3a+7=a 3 −3a 2 +3a−1+8=(a−1) 3 +8 But (a−1) 3 +8=(a−1) 3 +2 3 =(a−1+2)[(a−1) 2 −2(a−1)+4] Simplification gives [(a−1) 2 −2(a−1)+4]=a 2 −2a+2−2a+1+4=a 2 −4a+7 Thus we obtain a 3 −3a 2 +3a+7=(a+1)(a 2 −4a+7). |
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