67 The required amount of KBr (molar mass = 119) in gram to start the – InterviewSolution

1.	67 The required amount of KBr (molar mass = 119) in gram to start the precipitation of AgBr in 500 mL solution of 0.05 M AgNO will be :- (KSP of AgBr = 5 1013) (1) 1.19 109 g (2) 4 1011 g (3) 5.95 1010 g (4) 2.97 1010 g
Answer» 67 The required amount of KBr (molar mass = 119) in gram to start the precipitation of AgBr in 500 mL solution of 0.05 M AgNO will be :- (KSP of AgBr = 5 1013) (1) 1.19 109 g (2) 4 1011 g (3) 5.95 1010 g (4) 2.97 1010 g

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