1.

60-65 4 65-75 5 75-80 6 80-85 8 mean ​

Answer»

Answer:Converting the given data into frequency distribution table

Maths marks No. of students

(f) Cf

60-65 8 8

65-70 12 20

70-75 14 34

75-80 8 42

80-85 5 47

85-90 6 53

90-95 4 57

Σf=57

Here, N=57

Hence the median class =

2

N

​

=

2

57

​

=28.5

In the above table 70-75 is the median class and the respective cf is 20 (nearest to the value of 28.5)

Acc to ques, l

1

​

=70 (lower limit of median class)

CF=20 (C= cumulative frequency preceding the median class)

i=l

2

​

−l

1

​

=5 (WIDTH of class INTERVAL of median class)

f = 14 (frequency of median class)

Median=l

1

​

+

f

2

N

​

−C

​

×i=70+

14

28.5−20

​

×5

Median= 73.05 (A)

Step-by-step EXPLANATION:


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