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6.Whatwillbethediameterofthecirclewithparallelchordsoflength6cmand8cminonesideofthecentreandthedis-tancebetweentwochordsisonecentime-terB6 cm1 om8 cm​

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Answer:

Step-by-step explanation:

You can construct the center of the circle by:

drawing the perpendicular bisector of the longest chord (DASHED blue LINE).

Connecting two nearby endpoints of the two chords (red line), and drawing its perpendicular bisector as well (red dashed line).

The INTERSECTION of these two bisectors is the midpoint of the circle M.

Together with the shortest chord these two bisectors form a (GREEN) isosceles, with legs of length 4:

Now it is easy to see that that RADIUS equals \sqrt{(4)^{2}+(3)^{2}}=5


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