Saved Bookmarks
| 1. |
6. What is the percent yield of a reaction that produces 9.8 g of CO when 25.0 g of Fe3O4 reacts with excess carbon?Fe3O4 + 4C - 3Fe + 4CO |
|
Answer» he mass of Fe3O4 TAKEN = 25 gmTo Find:The percentage yield of the reaction.Calculation:- ACCORDING to the given reaction:The mass of CO PRODUCED by 232 gm of Fe3O4 = 112 gm⇒ The mass of CO produced by 25 gm of Fe3O4 = (112/232) × 25 gm⇒ The mass of CO produced by 25 gm of Fe3O4 = 12.07 gm⇒ Theoretical yield = 12.07 gm- Percentage yield = (Actual yield/Theoretical yield) × 100⇒ Percentage yield = (9.8/12.07) × 100⇒ Percentage yield = 81.193 %- So, the percentage yield of the reaction is 81.193%. |
|