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6. Two boxes A and B of weight 250 N and 150 N respectively are placed on an inclined surface as shown in figure 6. Determine value of a so that motion of boxes impends down theplane. Assume coefficient of static friction between block A and inclined surface as 0.30 andbetween block B and inclined surface as 0.20​

Answer»

A = Tan^-1 (0.3) downward F ALONG incline 《 FRICTIONAL Resistance FORCE CAUSED by STATIC Frictionmg sin theta 《 Mustatic x mg Cos Theta ( mg cos Theta is Normal Formal force from incline )Tan A 《 Mu = 0.3A = Tan^-1 0.3



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