6. The volume of a cuboid is 14400 cm3 and its height is 15 cm. The cr

1.	6. The volume of a cuboid is 14400 cm3 and its height is 15 cm. The cross-section of the cuboidis a rectangle having its sides in the ratio 5 3. Find the perimeter of the cross-section.n it with gravel 14 cm deep at the
Answer» Volume of a Cuboid = length* widthheight let length of a cuboid = 5x cm & width= 3x cm,Volume of a cuboid = 14400 cm3,Height=15cm substituting in formula, 14400 = 155x3x 14400=x2 1515 taking square root on both sides, we get 120/15 =x 8= x so length of a cuboid ( rectangula) =58=40cm width of a cuboid (rectangular)=38 =24 cm Perimeter of a cross section= 2(l+w) = 2(40+24)=2(64)=128cm

6. The volume of a cuboid is 14400 cm3 and its height is 15 cm. The cross-section of the cuboidis a rectangle having its sides in the ratio 5 3. Find the perimeter of the cross-section.n it with gravel 14 cm deep at the

Answer»

Volume of a Cuboid = length* width*height

let length of a cuboid = 5x cm & width= 3x cm,Volume of a cuboid = 14400 cm3,Height=15cm

substituting in formula,

14400 = 15*5x*3x

14400=x2

15*15

taking square root on both sides, we get

120/15 =x

8= x

so length of a cuboid ( rectangula) =5*8=40cm

width of a cuboid (rectangular)=3*8 =24 cm

Perimeter of a cross section= 2(l+w) = 2(40+24)=2(64)=128cm