6)The adjacent sides of a parallelogram measures 34 m, 20 m and the me

1.	6)The adjacent sides of a parallelogram measures 34 m, 20 m and the measure ofone of the diagonal is 42 m. Find the area of parallelogram
Answer» *ANSWER: The diagonal of a parallelogram divides it into TWO congruent triangles. Also, the area of the parallelogram is the sum of the areas of the triangles. We will now use Hero’s formula to calculate the area of TRIANGLE ABC. Semiperimeter, $\\ s = \frac{1}{2}(34 + 20 + 42) \\ = \frac{1}{2} (96)$ Area of ∆ ABC , $= > \sqrt{s(s - a)(s - b)(s - c)} \\$ $= > \sqrt{48(48 - 42)(48 - 34)(48 - 20)} \\$ $= > \sqrt{48 \times 6 \times 14 \times 28} \\$ $= > \sqrt{112826} \\$ $= > 336 \: {cm}^{2}$ Area of parallelogram = 2 × Area ∆ ABC => 2 × 336 $672 \: {cm}^{2}$

6)The adjacent sides of a parallelogram measures 34 m, 20 m and the measure ofone of the diagonal is 42 m. Find the area of parallelogram

Answer»

*ANSWER:

The diagonal of a parallelogram divides it into TWO congruent triangles. Also, the area of the parallelogram is the sum of the areas of the triangles.

We will now use Hero’s formula to calculate the area of TRIANGLE ABC.

Semiperimeter,

$\\ s = \frac{1}{2}(34 + 20 + 42) \\ = \frac{1}{2} (96)$