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6 months. How much rent did it pay?14. The perimeter of an isosceles triangle is 42 cm and its base is 15 timeseach of the equal sides. Find (1) the length of each side of the triangle,(ii) the area of the triangle, and (iii) the height of the triangle. (Given,V7 = 2.64.) |
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Answer» I don't know iwant coins so let each equal sides be xcm base= 1½x=(3/2)xPerimeter=42cmx+x+(3/2)x=42cm(2x+2x+3x)=84[multiply by 2 both sides]7x=84x=84/7x=12 cm(i) length of each sides=xcm,xcm,(3/2)cm=12cm,12cm,(3/2)*12cm=12cm,12cm and 18cm.(ii)a=12cm,b=12cm,c=18cmSemiperimeter=(a+b+c)/2=(12+12+18)/2=42/2=21cmArea=√S(S-a)(S-b)(S-c)=√21(21-12)(21-12)(21-18)=√21x9x9x3=√3x7x9²x3=√3²x9²x7=3x9√7=27√7 cm²(iii) (iii)Area=27√71/2xbasexheight=27√71/2x18xheight=27√79xheight=27√7height=27√7/9 =3√7 =3x2.64 =7.92cm patani ki eda answer..... 27√7 cm^2 is the right answer 27√7 is the right answer |
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