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6.Mohit was looking for his father. He went 90 metres in theEast before turning to his right. He went 20 metres beforeturning to his right, again to look for his father at his uncle'splace 30 metres from this point. His father was not there.From there he went 100 metres to the North before meetinghis father in a street. How far did the son meet his fatherfrom the starting point? |
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Answer» Also DE = 100 metre, DF = BC = 20 metreSo, EF = DE - DF = 80 metre as we can see in image that triangle AFE is a right angled triangle and we are having two sides, need to calculate third one, so we can apply Pythagoras theorem here A = AE = \sqrt{AF^2 + EF^2} \\= \sqrt{(60)^2+(80)^2} \\= \sqrt{3600+6400} \\= \sqrt{10000} = 100 So from starting point his father was 100 metre away. |
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