Saved Bookmarks
| 1. |
6.) In the figure, OACB is aquadrant of a circle with centreO and radius 3.5cm. IfOD=2cm, find the area of theshaded region.(use π= 22/7) |
|
Answer» Answer: 6.125cm^2 Explanation: πr^2 / 4 22/7 x 3.5 x 3.5 / 4 = 9.625cm^2 Area of triangle ODB:- 1/2 x B x h 1/2 x 2 x 3.5 = 3.5cm^2 So, area of SHADED part = 9.625 - 3.5 = 6.125cm^2 |
|