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6.) In the figure, OACB is aquadrant of a circle with centreO and radius 3.5cm. IfOD=2cm, find the area of theshaded region.(use π= 22/7)​

Answer»

Answer:

6.125cm^2

Explanation:

AREA of WHOLE quadrant:-

πr^2 / 4

22/7 x 3.5 x 3.5 / 4 = 9.625cm^2

Area of triangle ODB:-

1/2 x B x h

1/2 x 2 x 3.5 = 3.5cm^2

So, area of SHADED part = 9.625 - 3.5 = 6.125cm^2



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