1.

6. For an A.P. -3, -7, -11, ..., find the value of t30-tz, withoutfinding the actual values of t3, and t20.1-7-- 11​

Answer»

Answer:

d=-7-(-3)

=-7+3

=-4

a=-3,n=30,d=-4

tn=a+(n-1)d

t30=-3+(30-1)(-4)

=-3+28×(-4)

=-3+(-112)

=-3-112

=-115

I THINK this answer is true

I am not sure about this answer



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