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6. For an A.P. -3, -7, -11, ..., find the value of t30-tz, withoutfinding the actual values of t3, and t20.1-7-- 11 |
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Answer» Answer: d=-7-(-3) =-7+3 =-4 a=-3,n=30,d=-4 tn=a+(n-1)d t30=-3+(30-1)(-4) =-3+28×(-4) =-3+(-112) =-3-112 =-115 I THINK this answer is true I am not sure about this answer |
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