6. Construct a AABC in which BC = 4.8 cm, B = 45° and 2C = 75Measure

1.	6. Construct a AABC in which BC = 4.8 cm, B = 45° and 2C = 75Measure ZA
Answer» a according to triangle sum property, sum of all angles= 180so, 45+75+A= 180120+A= 180A= 180-120A= 60 a+b+ c =180a+45+75=180a=180-120a=60 sum of all angles in triangle =180° : angle A+angle B+angle C=180 x+45+75=180 x+120=180x=180-120x=60angle A=60° By angle sum property of triangleA + B + C = 180° A + 45° + 75° = 180°A = 180° - 120° A = 60°

6. Construct a AABC in which BC = 4.8 cm, B = 45° and 2C = 75Measure ZA

Answer»

according to triangle sum property, sum of all angles= 180so, 45+75+A= 180120+A= 180A= 180-120A= 60

a+b+ c =180a+45+75=180a=180-120a=60

sum of all angles in triangle =180° : angle A+angle B+angle C=180 x+45+75=180 x+120=180x=180-120x=60angle A=60°

By angle sum property of triangleA + B + C = 180° A + 45° + 75° = 180°A = 180° - 120° A = 60°