6 by 3 root 2 - 2 root 3 = a root 2 - b root 3 find and b

1.	6 by 3 root 2 - 2 root 3 = a root 2 - b root 3 find and b
Answer» Answer: We can MULTIPLY both top and bottom by 3+√2 (the CONJUGATE of 3−√2), which won't change the value of the fraction: 13−√2 × 3+√23+√2 = 3+√232−(√2)2 = 3+√27 (The denominator becomes (a+b)(a−b) = a2 − b2 which simplifies to 9−2=7) mark it as branlist ..follow me PLS..

Answer»

Answer:

We can MULTIPLY both top and bottom by 3+√2 (the CONJUGATE of 3−√2), which won't change the value of the fraction:

13−√2 × 3+√23+√2 = 3+√232−(√2)2 = 3+√27

(The denominator becomes (a+b)(a−b) = a2 − b2 which simplifies to 9−2=7)

mark it as branlist

..follow me PLS..

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6 by 3 root 2 - 2 root 3 = a root 2 - b root 3 find and b​