6. AB is diam16.a diameter of a circle. AH and BK are perpendiculars from A and B respectively to the tangent at P: Provethat AH + BKAB.tnnother triangle whose

6. AB is diam16.a diameter of a circle. AH and BK are perpendiculars f

1.	6. AB is diam16.a diameter of a circle. AH and BK are perpendiculars from A and B respectively to the tangent at P: Provethat AH + BKAB.tnnother triangle whose
Answer» SOLUTION:[FIGURE IS IN THE ATTACHMENT]Given:AH and BK are perpendiculars drawn from A and B on tangent at P.To Prove:AH + BK = ABPROOF:ABKH is a rectangle.(AH & BK are Perpendiculars.AB = HK …..…….....(1)[Opposite sides of rectangle are equal]We know that, the lengths of tangents drawn from an external point to the circle are equal.AH = HP ……............(2)BK = PK ..….............(3)Adding eq. (2) and (3), AH + BK = HP + PK = HKAH + BK = AB [from eq. (1)]