6. A student goes to school at the rate of 20 km/h and reaches 6 minut

1.	6. A student goes to school at the rate of 20 km/h and reaches 6 minutes late. Iftravels at the speed of 3 km/h, he is 10 minutes early. What is the distance to school?
Answer» speed :- 2 1/2 = 2.5 km/hr6 min = 0.1 hour10 min = 0.16 hour distance = time differenceproduct of speeds / difference of speed time taken = 6 min + 10 min = 16 min = 0.267 hourproduct of speed = 2.53 = 7.5difference of speed = 3 - 2.5 = 0.5 applying the formula , distance = 0.267*7.5/0.5 = 2.0025 /0.5 = 4.005 km = 4 km (approx.) Like my answer if you find it useful!

6. A student goes to school at the rate of 20 km/h and reaches 6 minutes late. Iftravels at the speed of 3 km/h, he is 10 minutes early. What is the distance to school?

Answer»

speed :- 2 1/2 = 2.5 km/hr6 min = 0.1 hour10 min = 0.16 hour

distance = time difference*product of speeds / difference of speed

time taken = 6 min + 10 min = 16 min = 0.267 hourproduct of speed = 2.5*3 = 7.5difference of speed = 3 - 2.5 = 0.5

applying the formula ,

distance = 0.267*7.5/0.5 = 2.0025 /0.5 = 4.005 km = 4 km (approx.)

Like my answer if you find it useful!