6. A particle starts moving at t = 0 from origin alongthe (+ve) direction of x-axis. Its speed depends ondxthe distance travelled x as v = KX. If v=dtdvthen find x, v and a in terms of timedtand a =K2t2 kt K24 2 2(2)K22 kt K24 2 2(3)Kt? Kt2 K4 2 2(4)Kt2 kt K4 '2'2

6. A particle starts moving at t = 0 from origin alongthe (+ve) dire

1.	6. A particle starts moving at t = 0 from origin alongthe (+ve) direction of x-axis. Its speed depends ondxthe distance travelled x as v = KX. If v=dtdvthen find x, v and a in terms of timedtand a =K2t2 kt K24 2 2(2)K22 kt K24 2 2(3)Kt? Kt2 K4 2 2(4)Kt2 kt K4 '2'2
Answer» V = k√xdx/dt = k√xdx/√x = kdtintegerating both side2√x = KTX = k2t2/4v = dx/dt = k2t/2a = dv/dt = k2/2Hope it CLEARS......

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6. A particle starts moving at t = 0 from origin alongthe (+ve) direction of x-axis. Its speed depends ondxthe distance travelled x as v = KX. If v=dtdvthen find x, v and a in terms of timedtand a =K2t2 kt K24 2 2(2)K22 kt K24 2 2(3)Kt? Kt2 K4 2 2(4)Kt2 kt K4 '2'2​

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6. A particle starts moving at t = 0 from origin alongthe (+ve) direction of x-axis. Its speed depends ondxthe distance travelled x as v = KX. If v=dtdvthen find x, v and a in terms of timedtand a =K2t2 kt K24 2 2(2)K22 kt K24 2 2(3)Kt? Kt2 K4 2 2(4)Kt2 kt K4 '2'2